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(11x-18)(6x+10)=0
We multiply parentheses ..
(+66x^2+110x-108x-180)=0
We get rid of parentheses
66x^2+110x-108x-180=0
We add all the numbers together, and all the variables
66x^2+2x-180=0
a = 66; b = 2; c = -180;
Δ = b2-4ac
Δ = 22-4·66·(-180)
Δ = 47524
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{47524}=218$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-218}{2*66}=\frac{-220}{132} =-1+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+218}{2*66}=\frac{216}{132} =1+7/11 $
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