(11x-12)=(3x+18)

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Solution for (11x-12)=(3x+18) equation: 



(11x-12)=(3x+18)

We move all terms to the left:

(11x-12)-((3x+18))=0

We get rid of parentheses

11x-((3x+18))-12=0



We calculate terms in parentheses: -((3x+18)), so:

(3x+18)

We get rid of parentheses

3x+18

Back to the equation:

-(3x+18)



We get rid of parentheses

11x-3x-18-12=0

We add all the numbers together, and all the variables

8x-30=0

We move all terms containing x to the left, all other terms to the right

8x=30

x=30/8

x=3+3/4

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