(11x-1)=(20x-3)+(29)=180

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Solution for (11x-1)=(20x-3)+(29)=180 equation: 



(11x-1)=(20x-3)+(29)=180

We move all terms to the left:

(11x-1)-((20x-3)+(29))=0

We get rid of parentheses

11x-((20x-3)+29)-1=0



We calculate terms in parentheses: -((20x-3)+29), so:

(20x-3)+29

We get rid of parentheses

20x-3+29

We add all the numbers together, and all the variables

20x+26

Back to the equation:

-(20x+26)



We get rid of parentheses

11x-20x-26-1=0

We add all the numbers together, and all the variables

-9x-27=0

We move all terms containing x to the left, all other terms to the right

-9x=27

x=27/-9

x=-3

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