(11x-1)(3x+6)=0

Solution for (11x-1)(3x+6)=0 equation:

(11x-1)(3x+6)=0

We multiply parentheses ..

(+33x^2+66x-3x-6)=0

We get rid of parentheses

33x^2+66x-3x-6=0

We add all the numbers together, and all the variables

33x^2+63x-6=0

a = 33; b = 63; c = -6;
Δ = b2-4ac
Δ = 632-4·33·(-6)
Δ = 4761
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4761}=69$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(63)-69}{2*33}=\frac{-132}{66}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(63)+69}{2*33}=\frac{6}{66}
=1/11
$