(11x+7)/5=(3x-8)/9

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Solution for (11x+7)/5=(3x-8)/9 equation: 



(11x+7)/5=(3x-8)/9

We move all terms to the left:

(11x+7)/5-((3x-8)/9)=0

We calculate fractions


11x/()+(-((3x-8)*5)/()=0



We calculate terms in parentheses: +(-((3x-8)*5)/(), so:

-((3x-8)*5)/(

We multiply all the terms by the denominator


-((3x-8)*5)



We calculate terms in parentheses: -((3x-8)*5), so:

(3x-8)*5

We multiply parentheses

15x-40

Back to the equation:

-(15x-40)



We get rid of parentheses

-15x+40

Back to the equation:

+(-15x+40)



We get rid of parentheses

11x/()-15x+40=0

We multiply all the terms by the denominator


11x-15x*()+40*()=0

We add all the numbers together, and all the variables

11x-15x*()=0

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