(11x+4)(8x+5)=180

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Solution for (11x+4)(8x+5)=180 equation:



(11x+4)(8x+5)=180
We move all terms to the left:
(11x+4)(8x+5)-(180)=0
We multiply parentheses ..
(+88x^2+55x+32x+20)-180=0
We get rid of parentheses
88x^2+55x+32x+20-180=0
We add all the numbers together, and all the variables
88x^2+87x-160=0
a = 88; b = 87; c = -160;
Δ = b2-4ac
Δ = 872-4·88·(-160)
Δ = 63889
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(87)-\sqrt{63889}}{2*88}=\frac{-87-\sqrt{63889}}{176} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(87)+\sqrt{63889}}{2*88}=\frac{-87+\sqrt{63889}}{176} $

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