(11x+2)+(7x-10)+47=180

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Solution for (11x+2)+(7x-10)+47=180 equation: 



(11x+2)+(7x-10)+47=180

We move all terms to the left:

(11x+2)+(7x-10)+47-(180)=0

We add all the numbers together, and all the variables

(11x+2)+(7x-10)-133=0

We get rid of parentheses

11x+7x+2-10-133=0

We add all the numbers together, and all the variables

18x-141=0

We move all terms containing x to the left, all other terms to the right

18x=141

x=141/18

x=7+5/6

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