(11c+8)(3c-6)=0

Solution for (11c+8)(3c-6)=0 equation:

(11c+8)(3c-6)=0

We multiply parentheses ..

(+33c^2-66c+24c-48)=0

We get rid of parentheses

33c^2-66c+24c-48=0

We add all the numbers together, and all the variables

33c^2-42c-48=0

a = 33; b = -42; c = -48;
Δ = b2-4ac
Δ = -422-4·33·(-48)
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8100}=90$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-42)-90}{2*33}=\frac{-48}{66}
=-8/11
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-42)+90}{2*33}=\frac{132}{66}
=2
$