(116)3x=642(x+8)(116)3x=642(x+8)

Solution for (116)3x=642(x+8)(116)3x=642(x+8) equation:

(116)3x=642(x+8)(116)3x=642(x+8)

We move all terms to the left:

(116)3x-(642(x+8)(116)3x)=0


We calculate terms in parentheses: -(642(x+8)1163x), so:

642(x+8)1163x

We multiply parentheses

746646x^2+5973168x

Back to the equation:

-(746646x^2+5973168x)


We get rid of parentheses

-746646x^2+1163x-5973168x=0

We add all the numbers together, and all the variables

-746646x^2-5972005x=0

a = -746646; b = -5972005; c = 0;
Δ = b2-4ac
Δ = -59720052-4·(-746646)·0
Δ = 35664843720025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{35664843720025}=5972005$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5972005)-5972005}{2*-746646}=\frac{0}{-1493292}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5972005)+5972005}{2*-746646}=\frac{11944010}{-1493292}
=-7+641/642
$