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(114+3)=1/3p
We move all terms to the left:
(114+3)-(1/3p)=0
Domain of the equation: 3p)!=0We add all the numbers together, and all the variables
p!=0/1
p!=0
p∈R
-(+1/3p)+117=0
We get rid of parentheses
-1/3p+117=0
We multiply all the terms by the denominator
117*3p-1=0
Wy multiply elements
351p-1=0
We move all terms containing p to the left, all other terms to the right
351p=1
p=1/351
p=1/351
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