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(11/x+2)-(3x+2/x)=0
Domain of the equation: x+2)!=0
x∈R
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(11/x+2)-(+3x+2/x)=0
We get rid of parentheses
11/x-3x-2/x+2=0
We multiply all the terms by the denominator
-3x*x+2*x+11-2=0
We add all the numbers together, and all the variables
2x-3x*x+9=0
Wy multiply elements
-3x^2+2x+9=0
a = -3; b = 2; c = +9;
Δ = b2-4ac
Δ = 22-4·(-3)·9
Δ = 112
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{112}=\sqrt{16*7}=\sqrt{16}*\sqrt{7}=4\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-4\sqrt{7}}{2*-3}=\frac{-2-4\sqrt{7}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+4\sqrt{7}}{2*-3}=\frac{-2+4\sqrt{7}}{-6} $
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