If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(11/8)z-(13/6)=(5/6)
We move all terms to the left:
(11/8)z-(13/6)-((5/6))=0
Domain of the equation: 8)z!=0We add all the numbers together, and all the variables
z!=0/1
z!=0
z∈R
(+11/8)z-(+13/6)-((+5/6))=0
We multiply parentheses
11z^2-(+13/6)-((+5/6))=0
We get rid of parentheses
11z^2-13/6-((+5/6))=0
We calculate fractions
11z^2=0
a = 11; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·11·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$z=\frac{-b}{2a}=\frac{0}{22}=0$
| (6x+5)+(4x-5)=180 | | 1.1/2=x | | 5x=12x-15 | | -5x(-15)=30 | | x-0.05x=13585 | | 18x+(-24)=48 | | V=1/3(3.14)r2 | | 122=45+4.05x | | 45+4.05x=122 | | -8y-5=7y-6 | | 12n^2-13n-35=0 | | 4/22/3=3/n | | 4x+6+2x+8+6x-26=180 | | 5x+10=210-x | | 1/2x-15=-5 | | 15x+10=210+x | | -5y-4=4y-5 | | (3x/5)+4=20-x | | 11+34=-5(4x-9) | | 3=66/v | | 5x+10=210+x | | 30/u=6 | | 34/w=2 | | 2x^2+0.6x+30=0 | | 4=92/u | | 5-x=1/9(4-x)-1/2(3x-3) | | G(x)=10(2^-x-1) | | 16250=(1÷2)(65)(250+b) | | -(-3)^3-(-2)-2^2-(-k-3)=-4^2-(3k-4) | | 2z+30=2(5z+3) | | 5(v-6)=-5 | | x-7=12-x |