(11-k)=3(3k-9)

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Solution for (11-k)=3(3k-9) equation: 



(11-k)=3(3k-9)

We move all terms to the left:

(11-k)-(3(3k-9))=0

We add all the numbers together, and all the variables

(-1k+11)-(3(3k-9))=0

We get rid of parentheses

-1k-(3(3k-9))+11=0



We calculate terms in parentheses: -(3(3k-9)), so:

3(3k-9)

We multiply parentheses

9k-27

Back to the equation:

-(9k-27)



We get rid of parentheses

-1k-9k+27+11=0

We add all the numbers together, and all the variables

-10k+38=0

We move all terms containing k to the left, all other terms to the right

-10k=-38

k=-38/-10

k=3+4/5

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