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(11+5x)/(3+x)=x
We move all terms to the left:
(11+5x)/(3+x)-(x)=0
Domain of the equation: (3+x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
x!=-3
x∈R
(5x+11)/(x+3)-x=0
We add all the numbers together, and all the variables
-1x+(5x+11)/(x+3)=0
We multiply all the terms by the denominator
-1x*(x+3)+(5x+11)=0
We multiply parentheses
-x^2-3x+(5x+11)=0
We get rid of parentheses
-x^2-3x+5x+11=0
We add all the numbers together, and all the variables
-1x^2+2x+11=0
a = -1; b = 2; c = +11;
Δ = b2-4ac
Δ = 22-4·(-1)·11
Δ = 48
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{48}=\sqrt{16*3}=\sqrt{16}*\sqrt{3}=4\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-4\sqrt{3}}{2*-1}=\frac{-2-4\sqrt{3}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+4\sqrt{3}}{2*-1}=\frac{-2+4\sqrt{3}}{-2} $
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