(11+2x)/5=(4x-5)/10

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Solution for (11+2x)/5=(4x-5)/10 equation: 



(11+2x)/5=(4x-5)/10

We move all terms to the left:

(11+2x)/5-((4x-5)/10)=0

We add all the numbers together, and all the variables

(2x+11)/5-((4x-5)/10)=0

We calculate fractions


2x/()+(-((4x-5)*5)/()=0



We calculate terms in parentheses: +(-((4x-5)*5)/(), so:

-((4x-5)*5)/(

We multiply all the terms by the denominator


-((4x-5)*5)



We calculate terms in parentheses: -((4x-5)*5), so:

(4x-5)*5

We multiply parentheses

20x-25

Back to the equation:

-(20x-25)



We get rid of parentheses

-20x+25

Back to the equation:

+(-20x+25)



We get rid of parentheses

2x/()-20x+25=0

We multiply all the terms by the denominator


2x-20x*()+25*()=0

We add all the numbers together, and all the variables

2x-20x*()=0

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