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(11+10x)(11-10x)=121
We move all terms to the left:
(11+10x)(11-10x)-(121)=0
We add all the numbers together, and all the variables
(10x+11)(-10x+11)-121=0
We multiply parentheses ..
(-100x^2+110x-110x+121)-121=0
We get rid of parentheses
-100x^2+110x-110x+121-121=0
We add all the numbers together, and all the variables
-100x^2=0
a = -100; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-100)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{-200}=0$
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