(10y-40)=(6y+20)

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Solution for (10y-40)=(6y+20) equation: 



(10y-40)=(6y+20)

We move all terms to the left:

(10y-40)-((6y+20))=0

We get rid of parentheses

10y-((6y+20))-40=0



We calculate terms in parentheses: -((6y+20)), so:

(6y+20)

We get rid of parentheses

6y+20

Back to the equation:

-(6y+20)



We get rid of parentheses

10y-6y-20-40=0

We add all the numbers together, and all the variables

4y-60=0

We move all terms containing y to the left, all other terms to the right

4y=60

y=60/4

y=15

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