(10y-12)/4=(4-2y)/6

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Solution for (10y-12)/4=(4-2y)/6 equation: 


y in (-oo:+oo)

(10*y-12)/4 = (4-(2*y))/6 // - (4-(2*y))/6

(10*y-12)/4-((4-(2*y))/6) = 0

(10*y-12)/4-((4-2*y)/6) = 0

(10*y-12)/4+(-1*(4-2*y))/6 = 0

(6*(10*y-12))/(4*6)+(-1*4*(4-2*y))/(4*6) = 0

6*(10*y-12)-1*4*(4-2*y) = 0

68*y-88 = 0

(68*y-88)/(4*6) = 0

(68*y-88)/(4*6) = 0 // * 4*6

68*y-88 = 0

68*y-88 = 0 // + 88

68*y = 88 // : 68

y = 88/68

y = 22/17

y = 22/17

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