(10x2)=(9x+18)

Solution for (10x2)=(9x+18) equation:

(10x^2)=(9x+18)

We move all terms to the left:

(10x^2)-((9x+18))=0


We calculate terms in parentheses: -((9x+18)), so:

(9x+18)

We get rid of parentheses

9x+18

Back to the equation:

-(9x+18)


We get rid of parentheses

10x^2-9x-18=0

a = 10; b = -9; c = -18;
Δ = b2-4ac
Δ = -92-4·10·(-18)
Δ = 801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{801}=\sqrt{9*89}=\sqrt{9}*\sqrt{89}=3\sqrt{89}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-3\sqrt{89}}{2*10}=\frac{9-3\sqrt{89}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+3\sqrt{89}}{2*10}=\frac{9+3\sqrt{89}}{20}
$