(10x-6)+7-8x=40

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Solution for (10x-6)+7-8x=40 equation: 



(10x-6)+7-8x=40

We move all terms to the left:

(10x-6)+7-8x-(40)=0

We add all the numbers together, and all the variables

-8x+(10x-6)-33=0

We get rid of parentheses

-8x+10x-6-33=0

We add all the numbers together, and all the variables

2x-39=0

We move all terms containing x to the left, all other terms to the right

2x=39

x=39/2

x=19+1/2

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