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(10x-42)=(4x+36)
We move all terms to the left:
(10x-42)-((4x+36))=0
We get rid of parentheses
10x-((4x+36))-42=0
We calculate terms in parentheses: -((4x+36)), so:We get rid of parentheses
(4x+36)
We get rid of parentheses
4x+36
Back to the equation:
-(4x+36)
10x-4x-36-42=0
We add all the numbers together, and all the variables
6x-78=0
We move all terms containing x to the left, all other terms to the right
6x=78
x=78/6
x=13
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