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(10x-3)/(2x-1)=5+2/2x-1
We move all terms to the left:
(10x-3)/(2x-1)-(5+2/2x-1)=0
Domain of the equation: (2x-1)!=0
We move all terms containing x to the left, all other terms to the right
2x!=1
x!=1/2
x!=1/2
x∈R
Domain of the equation: 2x-1)!=0We add all the numbers together, and all the variables
x∈R
(10x-3)/(2x-1)-(2/2x+4)=0
We get rid of parentheses
(10x-3)/(2x-1)-2/2x-4=0
We calculate fractions
(20x^2-6x)/(4x^2-2x)+(-4x+2)/(4x^2-2x)-4=0
We multiply all the terms by the denominator
(20x^2-6x)+(-4x+2)-4*(4x^2-2x)=0
We multiply parentheses
-16x^2+(20x^2-6x)+(-4x+2)+8x=0
We get rid of parentheses
-16x^2+20x^2-6x-4x+8x+2=0
We add all the numbers together, and all the variables
4x^2-2x+2=0
a = 4; b = -2; c = +2;
Δ = b2-4ac
Δ = -22-4·4·2
Δ = -28
Delta is less than zero, so there is no solution for the equation
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