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(10x-3)(2x+7)=0
We multiply parentheses ..
(+20x^2+70x-6x-21)=0
We get rid of parentheses
20x^2+70x-6x-21=0
We add all the numbers together, and all the variables
20x^2+64x-21=0
a = 20; b = 64; c = -21;
Δ = b2-4ac
Δ = 642-4·20·(-21)
Δ = 5776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5776}=76$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-76}{2*20}=\frac{-140}{40} =-3+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+76}{2*20}=\frac{12}{40} =3/10 $
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