(10x-24)(7x-18)=(5x+2)

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Solution for (10x-24)(7x-18)=(5x+2) equation:



(10x-24)(7x-18)=(5x+2)
We move all terms to the left:
(10x-24)(7x-18)-((5x+2))=0
We multiply parentheses ..
(+70x^2-180x-168x+432)-((5x+2))=0
We calculate terms in parentheses: -((5x+2)), so:
(5x+2)
We get rid of parentheses
5x+2
Back to the equation:
-(5x+2)
We get rid of parentheses
70x^2-180x-168x-5x+432-2=0
We add all the numbers together, and all the variables
70x^2-353x+430=0
a = 70; b = -353; c = +430;
Δ = b2-4ac
Δ = -3532-4·70·430
Δ = 4209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-353)-\sqrt{4209}}{2*70}=\frac{353-\sqrt{4209}}{140} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-353)+\sqrt{4209}}{2*70}=\frac{353+\sqrt{4209}}{140} $

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