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(10x-2)(6x-6)=0
We multiply parentheses ..
(+60x^2-60x-12x+12)=0
We get rid of parentheses
60x^2-60x-12x+12=0
We add all the numbers together, and all the variables
60x^2-72x+12=0
a = 60; b = -72; c = +12;
Δ = b2-4ac
Δ = -722-4·60·12
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-48}{2*60}=\frac{24}{120} =1/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+48}{2*60}=\frac{120}{120} =1 $
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