(10x+6)(8x-6)=180

Solution for (10x+6)(8x-6)=180 equation:

(10x+6)(8x-6)=180

We move all terms to the left:

(10x+6)(8x-6)-(180)=0

We multiply parentheses ..

(+80x^2-60x+48x-36)-180=0

We get rid of parentheses

80x^2-60x+48x-36-180=0

We add all the numbers together, and all the variables

80x^2-12x-216=0

a = 80; b = -12; c = -216;
Δ = b2-4ac
Δ = -122-4·80·(-216)
Δ = 69264
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{69264}=\sqrt{144*481}=\sqrt{144}*\sqrt{481}=12\sqrt{481}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-12\sqrt{481}}{2*80}=\frac{12-12\sqrt{481}}{160}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+12\sqrt{481}}{2*80}=\frac{12+12\sqrt{481}}{160}
$