(10x+52)+(6x)=180

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Solution for (10x+52)+(6x)=180 equation: 



(10x+52)+(6x)=180

We move all terms to the left:

(10x+52)+(6x)-(180)=0

We add all the numbers together, and all the variables

6x+(10x+52)-180=0

We get rid of parentheses

6x+10x+52-180=0

We add all the numbers together, and all the variables

16x-128=0

We move all terms containing x to the left, all other terms to the right

16x=128

x=128/16

x=8

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