(10x+5)=(16x-79)

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Solution for (10x+5)=(16x-79) equation: 



(10x+5)=(16x-79)

We move all terms to the left:

(10x+5)-((16x-79))=0

We get rid of parentheses

10x-((16x-79))+5=0



We calculate terms in parentheses: -((16x-79)), so:

(16x-79)

We get rid of parentheses

16x-79

Back to the equation:

-(16x-79)



We get rid of parentheses

10x-16x+79+5=0

We add all the numbers together, and all the variables

-6x+84=0

We move all terms containing x to the left, all other terms to the right

-6x=-84

x=-84/-6

x=+14

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