(10x+5)/78=(6x-1)/42

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Solution for (10x+5)/78=(6x-1)/42 equation: 



(10x+5)/78=(6x-1)/42

We move all terms to the left:

(10x+5)/78-((6x-1)/42)=0

We calculate fractions


10x/()+(-((6x-1)*78)/()=0



We calculate terms in parentheses: +(-((6x-1)*78)/(), so:

-((6x-1)*78)/(

We multiply all the terms by the denominator


-((6x-1)*78)



We calculate terms in parentheses: -((6x-1)*78), so:

(6x-1)*78

We multiply parentheses

468x-78

Back to the equation:

-(468x-78)



We get rid of parentheses

-468x+78

Back to the equation:

+(-468x+78)



We get rid of parentheses

10x/()-468x+78=0

We multiply all the terms by the denominator


10x-468x*()+78*()=0

We add all the numbers together, and all the variables

10x-468x*()=0

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