(10x+5)(11x-44)=0

Solution for (10x+5)(11x-44)=0 equation:

(10x+5)(11x-44)=0

We multiply parentheses ..

(+110x^2-440x+55x-220)=0

We get rid of parentheses

110x^2-440x+55x-220=0

We add all the numbers together, and all the variables

110x^2-385x-220=0

a = 110; b = -385; c = -220;
Δ = b2-4ac
Δ = -3852-4·110·(-220)
Δ = 245025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{245025}=495$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-385)-495}{2*110}=\frac{-110}{220}
=-1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-385)+495}{2*110}=\frac{880}{220}
=4
$