(10x+1)=(3x+18)+(3x+11)

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Solution for (10x+1)=(3x+18)+(3x+11) equation: 



(10x+1)=(3x+18)+(3x+11)

We move all terms to the left:

(10x+1)-((3x+18)+(3x+11))=0

We get rid of parentheses

10x-((3x+18)+(3x+11))+1=0



We calculate terms in parentheses: -((3x+18)+(3x+11)), so:

(3x+18)+(3x+11)

We get rid of parentheses

3x+3x+18+11

We add all the numbers together, and all the variables

6x+29

Back to the equation:

-(6x+29)



We get rid of parentheses

10x-6x-29+1=0

We add all the numbers together, and all the variables

4x-28=0

We move all terms containing x to the left, all other terms to the right

4x=28

x=28/4

x=7

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