(100-15x)-5x=(40+40x)-(100-10x)

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Solution for (100-15x)-5x=(40+40x)-(100-10x) equation: 



(100-15x)-5x=(40+40x)-(100-10x)

We move all terms to the left:

(100-15x)-5x-((40+40x)-(100-10x))=0

We add all the numbers together, and all the variables

(-15x+100)-5x-((40x+40)-(-10x+100))=0

We add all the numbers together, and all the variables

-5x+(-15x+100)-((40x+40)-(-10x+100))=0

We get rid of parentheses

-5x-15x-((40x+40)-(-10x+100))+100=0



We calculate terms in parentheses: -((40x+40)-(-10x+100)), so:

(40x+40)-(-10x+100)

We get rid of parentheses

40x+10x+40-100

We add all the numbers together, and all the variables

50x-60

Back to the equation:

-(50x-60)



We add all the numbers together, and all the variables

-20x-(50x-60)+100=0

We get rid of parentheses

-20x-50x+60+100=0

We add all the numbers together, and all the variables

-70x+160=0

We move all terms containing x to the left, all other terms to the right

-70x=-160

x=-160/-70

x=2+2/7

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