(100-10x)-(40+40x)=5x-(100-15x)

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Solution for (100-10x)-(40+40x)=5x-(100-15x) equation:



(100-10x)-(40+40x)=5x-(100-15x)
We move all terms to the left:
(100-10x)-(40+40x)-(5x-(100-15x))=0
We add all the numbers together, and all the variables
(-10x+100)-(40x+40)-(5x-(-15x+100))=0
We get rid of parentheses
-10x-40x-(5x-(-15x+100))+100-40=0
We calculate terms in parentheses: -(5x-(-15x+100)), so:
5x-(-15x+100)
We get rid of parentheses
5x+15x-100
We add all the numbers together, and all the variables
20x-100
Back to the equation:
-(20x-100)
We add all the numbers together, and all the variables
-50x-(20x-100)+60=0
We get rid of parentheses
-50x-20x+100+60=0
We add all the numbers together, and all the variables
-70x+160=0
We move all terms containing x to the left, all other terms to the right
-70x=-160
x=-160/-70
x=2+2/7

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