(100)=(1)-(11/2)n

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Solution for (100)=(1)-(11/2)n equation: 



(100)=(1)-(11/2)n

We move all terms to the left:

(100)-((1)-(11/2)n)=0



Domain of the equation: 2)n)!=0

n!=0/1

n!=0

n∈R



We add all the numbers together, and all the variables

-(1-(+11/2)n)+100=0

We multiply all the terms by the denominator


-(1-(+11+100*2)n)=0



We calculate terms in parentheses: -(1-(+11+100*2)n), so:

1-(+11+100*2)n

determiningTheFunctionDomain
-(+11+100*2)n+1

We add all the numbers together, and all the variables

-211n+1

Back to the equation:

-(-211n+1)



We get rid of parentheses

211n-1=0

We move all terms containing n to the left, all other terms to the right

211n=1

n=1/211

n=1/211

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