(10/x)+28=(2/3x)

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Solution for (10/x)+28=(2/3x) equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

10/x+28 = (2/3)*x // - (2/3)*x

10/x-((2/3)*x)+28 = 0

(-2/3)*x+10/x+28 = 0

10*x^-1-2/3*x^1+28*x^0 = 0

(28*x^1-2/3*x^2+10*x^0)/(x^1) = 0 // * x^2

x^1*(28*x^1-2/3*x^2+10*x^0) = 0

x^1

(-2/3)*x^2+28*x+10 = 0

(-2/3)*x^2+28*x+10 = 0

DELTA = 28^2-(4*10*(-2/3))

DELTA = 2432/3

DELTA > 0

x = ((2432/3)^(1/2)-28)/(2*(-2/3)) or x = (-(2432/3)^(1/2)-28)/(2*(-2/3))

x = -3/4*((2432/3)^(1/2)-28) or x = 3/4*((2432/3)^(1/2)+28)

x in { -3/4*((2432/3)^(1/2)-28), 3/4*((2432/3)^(1/2)+28)}

x in { -3/4*((2432/3)^(1/2)-28), 3/4*((2432/3)^(1/2)+28) }

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