(10/5x-7)=(15/5x-3)

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Solution for (10/5x-7)=(15/5x-3) equation: 



(10/5x-7)=(15/5x-3)

We move all terms to the left:

(10/5x-7)-((15/5x-3))=0



Domain of the equation: 5x-7)!=0

x∈R





Domain of the equation: 5x-3))!=0

x∈R



We get rid of parentheses

10/5x-((15/5x-3))-7=0

We calculate fractions


50x/25x^2+(-((15*5x)/25x^2-7=0

We add all the numbers together, and all the variables

50x/25x^2+(-((+15*5x)/25x^2-7=0

We calculate fractions

We do not support expression: x^4

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