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(10-f)(10-f)=0
We add all the numbers together, and all the variables
(-1f+10)(-1f+10)=0
We multiply parentheses ..
(+f^2-10f-10f+100)=0
We get rid of parentheses
f^2-10f-10f+100=0
We add all the numbers together, and all the variables
f^2-20f+100=0
a = 1; b = -20; c = +100;
Δ = b2-4ac
Δ = -202-4·1·100
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$f=\frac{-b}{2a}=\frac{20}{2}=10$
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