(10-2x)(5x-x)=50

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Solution for (10-2x)(5x-x)=50 equation: 



(10-2x)(5x-x)=50

We move all terms to the left:

(10-2x)(5x-x)-(50)=0

We add all the numbers together, and all the variables

(-2x+10)(+4x)-50=0

We multiply parentheses ..

(-8x^2+40x)-50=0

We get rid of parentheses

-8x^2+40x-50=0

a = -8; b = 40; c = -50;
Δ = b2-4ac
Δ = 402-4·(-8)·(-50)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-40}{-16}=2+1/2$

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