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(10+x)(9+x)=360
We move all terms to the left:
(10+x)(9+x)-(360)=0
We add all the numbers together, and all the variables
(x+10)(x+9)-360=0
We multiply parentheses ..
(+x^2+9x+10x+90)-360=0
We get rid of parentheses
x^2+9x+10x+90-360=0
We add all the numbers together, and all the variables
x^2+19x-270=0
a = 1; b = 19; c = -270;
Δ = b2-4ac
Δ = 192-4·1·(-270)
Δ = 1441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-\sqrt{1441}}{2*1}=\frac{-19-\sqrt{1441}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+\sqrt{1441}}{2*1}=\frac{-19+\sqrt{1441}}{2} $
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