(10+5x)5+-7x=40

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Solution for (10+5x)5+-7x=40 equation: 



(10+5x)5+-7x=40

We move all terms to the left:

(10+5x)5+-7x-(40)=0

determiningTheFunctionDomain
(10+5x)5-7x-40+=0

We add all the numbers together, and all the variables

(5x+10)5-7x-40+=0

We add all the numbers together, and all the variables

-7x+(5x+10)5=0

We multiply parentheses

-7x+25x+50=0

We add all the numbers together, and all the variables

18x+50=0

We move all terms containing x to the left, all other terms to the right

18x=-50

x=-50/18

x=-2+7/9

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