(10+5x)/(-1+x)=2

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Solution for (10+5x)/(-1+x)=2 equation: 


D( x )

x-1 = 0

x-1 = 0

x-1 = 0

x-1 = 0 // + 1

x = 1

x in (-oo:1) U (1:+oo)

(5*x+10)/(x-1) = 2 // - 2

(5*x+10)/(x-1)-2 = 0

(5*x+10)/(x-1)+(-2*(x-1))/(x-1) = 0

5*x-2*(x-1)+10 = 0

3*x+12 = 0

(3*x+12)/(x-1) = 0

(3*x+12)/(x-1) = 0 // * x-1

3*x+12 = 0

3*x+12 = 0 // - 12

3*x = -12 // : 3

x = -12/3

x = -4

x = -4

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