(10(y+2)/7)=2y-4

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Solution for (10(y+2)/7)=2y-4 equation: 



(10(y+2)/7)=2y-4

We move all terms to the left:

(10(y+2)/7)-(2y-4)=0

We get rid of parentheses

(10(y+2)/7)-2y+4=0

We multiply all the terms by the denominator


(10(y+2)-2y*7)+4*7)=0



We calculate terms in parentheses: +(10(y+2)-2y*7), so:

10(y+2)-2y*7

We multiply parentheses

10y-2y*7+20

Wy multiply elements

10y-14y+20

We add all the numbers together, and all the variables

-4y+20

Back to the equation:

+(-4y+20)



We add all the numbers together, and all the variables

(-4y+20)=0

We get rid of parentheses

-4y+20=0

We move all terms containing y to the left, all other terms to the right

-4y=-20

y=-20/-4

y=+5

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