(1/z)-(1/z+1)=3

Simple and best practice solution for (1/z)-(1/z+1)=3 equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

If it's not what You are looking for type in the equation solver your own equation and let us solve it.

Solution for (1/z)-(1/z+1)=3 equation: 


D( z )

z = 0

z = 0

z = 0

z in (-oo:0) U (0:+oo)

1/z-(1/z)-1 = 3 // - 3

1/z-(1/z)-3-1 = 0

1/z-z^-1-3-1 = 0

-4 = 0

z belongs to the empty set

z belongs to the empty set

See similar equations:

| 15.50=26-25p-2p | | 3x+3(1/6x-x)=5 | | 1/4^2+12=0 | | x/(-3)=12 | | 9-x+7x=21 | | -21=t+14 | | x+sqrt(x)=30 | | -3(x-3)=5x-7 | | 139-7x=9x+21 | | x-0.30x=92 | | 5/2+8=54 | | 4(3x+4)=4(2x+12) | | 1/7(x)=41 | | -3(1+7x)-4x=8-6(1+4x) | | 4(x)=1/2x+3 | | 624/27 | | 1+(1/7)=7 | | 4y=12x+40 | | 100x^2-169=0 | | -4p+2(p+5)=6p+2(1-6p) | | 49p-49=52p-97 | | 0.4x+2-0.6x+0.6=6 | | -2(5+6x)=4(x+2) | | v+(v-33.4)+(v+24.3)=196.1 | | z/5-6=(1)5/6 | | x^2+7x+150=0 | | 35x^3-25x^2+40x=0 | | 12x^2-20x-3=0 | | x/7-2=4 | | 5(7r+1)=5+6r | | 1344=96L | | 4/9x-5=11 |

Equations solver categories