(1/y)+(1/16)=(1/12)

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Solution for (1/y)+(1/16)=(1/12) equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

1/y+1/16 = 1/12 // - 1/12

1/y+1/16-(1/12) = 0

1/y+1/16-1/12 = 0

1*y^-1 = 1/48 // : 1

y^-1 = 1/48

-1 < 0

1/(y^1) = 1/48 // * y^1

1 = 1/48*y^1 // : 1/48

48 = y^1

y = 48

y = 48

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