(1/x2)+(7/x)+10=0

Solution for (1/x2)+(7/x)+10=0 equation:

D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

7/x+1/(x^2)+10 = 0

7*x^-1+x^-2+10 = 0

t_1 = x^-1

1*t_1^2+7*t_1^1+10 = 0

t_1^2+7*t_1+10 = 0

DELTA = 7^2-(1*4*10)

DELTA = 9

DELTA > 0

t_1 = (9^(1/2)-7)/(1*2) or t_1 = (-9^(1/2)-7)/(1*2)

t_1 = -2 or t_1 = -5

t_1 = -5

x^-1+5 = 0

1*x^-1 = -5 // : 1

x^-1 = -5

-1 < 0

1/(x^1) = -5 // * x^1

1 = -5*x^1 // : -5

-1/5 = x^1

x = -1/5

t_1 = -2

x^-1+2 = 0

1*x^-1 = -2 // : 1

x^-1 = -2

-1 < 0

1/(x^1) = -2 // * x^1

1 = -2*x^1 // : -2

-1/2 = x^1

x = -1/2

x in { -1/5, -1/2 }