(1/x+4)+(1/x-4)=(1/x+11)

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Solution for (1/x+4)+(1/x-4)=(1/x+11) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

1/x+1/x-4+4 = 1/x+11 // - 1/x+11

1/x+1/x-(1/x)-11-4+4 = 0

1/x+1/x-x^-1-11-4+4 = 0

1*x^-1 = 11 // : 1

x^-1 = 11

-1 < 0

1/(x^1) = 11 // * x^1

1 = 11*x^1 // : 11

1/11 = x^1

x = 1/11

x = 1/11

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