(1/x+1)+(1/X+2)=(3/x+1)

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Solution for (1/x+1)+(1/X+2)=(3/x+1) equation: 



(1/x+1)+(1/x+2)=(3/x+1)

We move all terms to the left:

(1/x+1)+(1/x+2)-((3/x+1))=0



Domain of the equation: x+1)!=0

x∈R





Domain of the equation: x+2)!=0

x∈R





Domain of the equation: x+1))!=0

x∈R



We get rid of parentheses

1/x+1/x-((3/x+1))+1+2=0

We calculate fractions


x/x^2+(-((3*x)/x^2+1+2=0

We add all the numbers together, and all the variables

x/x^2+(-((+3x)/x^2+1+2=0

We calculate fractions

We do not support expression: x^4

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