(1/x)-1/(x-2)=1/2

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Solution for (1/x)-1/(x-2)=1/2 equation: 


D( x )

x-2 = 0

x = 0

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

x = 0

x = 0

x in (-oo:0) U (0:2) U (2:+oo)

1/x-(1/(x-2)) = 1/2 // - 1/2

1/x-(1/(x-2))-(1/2) = 0

1/x-(x-2)^-1-1/2 = 0

1/x-1/(x-2)-1/2 = 0

(-1*2*x)/(2*x*(x-2))+(1*2*(x-2))/(2*x*(x-2))+(-1*x*(x-2))/(2*x*(x-2)) = 0

1*2*(x-2)-1*x*(x-2)-1*2*x = 0

2*x-x^2-4 = 0

2*x-x^2-4 = 0

2*x-x^2-4 = 0

DELTA = 2^2-(-4*(-1)*4)

DELTA = -12

DELTA < 0

1 = 0

1/(2*x*(x-2)) = 0

1/(2*x*(x-2)) = 0 // * 2*x*(x-2)

1 = 0

x belongs to the empty set

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