(1/x)-(3/(x-2))=0

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Solution for (1/x)-(3/(x-2))=0 equation: 



(1/x)-(3/(x-2))=0



Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R





Domain of the equation: (x-2))!=0

x∈R



We add all the numbers together, and all the variables

(+1/x)-(3/(x-2))=0

We get rid of parentheses

1/x-(3/(x-2))=0

We calculate fractions


-1x^2)+(-(3*x)/(-1x^2)+(1*(x-2)))/(=0

We add all the numbers together, and all the variables

-1x^2)+(-(+3x)/(-1x^2)+(1*(x-2)))/(=0

We calculate fractions


-1x^2)+(+(-(+3x)*()/((-1x^2)*()+(-1x^2)+(1*(x-2)))*()/((-1x^2)*()=0



We calculate terms in parentheses: +(-(+3x)*()/((-1x^2)*()+(-1x^2)+(1*(x-2)))*()/((-1x^2)*(), so:

-(+3x)*()/((-1x^2)*()+(-1x^2)+(1*(x-2)))*()/((-1x^2)*(

We can not solve this equation

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