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(1/x)-(1/x+1)=2
We move all terms to the left:
(1/x)-(1/x+1)-(2)=0
Domain of the equation: x)!=0
x!=0/1
x!=0
x∈R
Domain of the equation: x+1)!=0We add all the numbers together, and all the variables
x∈R
(+1/x)-(1/x+1)-2=0
We get rid of parentheses
1/x-1/x-1-2=0
We multiply all the terms by the denominator
-1*x-2*x+1-1=0
We add all the numbers together, and all the variables
-3x=0
x=0/-3
x=0
Równanie nie ma rozwiązania
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